# What are the total force and the absolute pressure on the bottom of a swimming pool 22.0 m by 8.5 m whose inform depth is 2.0 m? What will be the pressure against the side of the pool near the bottom?

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Find the pressure:

(Note: Absolute Pressure is the total pressure of the liquid + the pressure exerted by the atmosphere.)

Pressure absolute = Pressure atm + density x acceleration due to gravity x depth

(note atm means atmosphere)

P = 1.103x10^5Pa (101325 Pa) + 1000 kg/m3 x 9.8 m/s2 x 2.0 m

= 101325 Pa + 19600 N/m2

= 120925 Pa or 1.21 x 10^5 Pa

Find Total Force:

(Note: Total force is the total weight of the water)

Mass = Density of Water x Volume

m = 1000 kg/m3 x (22.0 m x 8.5 m x 2.0 m)

m = 1000 kg/m3 x 374 m3

m = 374 000 kg or 3.74 x 10^5 m3

Weight = Mass x Acceleration due to Gravity

W= 374 000 kg x 9.8 m/s

W = 3 665 200 Newtons or 3.67 x 10^6 N

(Note: Absolute Pressure is the total pressure of the liquid + the pressure exerted by the atmosphere.)

Pressure absolute = Pressure atm + density x acceleration due to gravity x depth

(note atm means atmosphere)

P = 1.103x10^5Pa (101325 Pa) + 1000 kg/m3 x 9.8 m/s2 x 2.0 m

= 101325 Pa + 19600 N/m2

= 120925 Pa or 1.21 x 10^5 Pa

Find Total Force:

(Note: Total force is the total weight of the water)

Mass = Density of Water x Volume

m = 1000 kg/m3 x (22.0 m x 8.5 m x 2.0 m)

m = 1000 kg/m3 x 374 m3

m = 374 000 kg or 3.74 x 10^5 m3

Weight = Mass x Acceleration due to Gravity

W= 374 000 kg x 9.8 m/s

W = 3 665 200 Newtons or 3.67 x 10^6 N