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Use the formula: 
y=a x^{2} +bx+c

a x^{2} (quadratic term)
bx (linear term)
c (constant)

3x-2 x^{2} =7

-2 x^{2} +3x=7 or -1(-2 x^{2} +3x = 7) -> 2 x^{2} -3x=-7

Just do the same thing to the other equations. But before you change it to standard form remember to simplify it. Good luck :)
Click "thanks" if I helped. It'll be appreciated. :)

1 5 1
i can understand im so very confused
That's contradicting, You can understand but you're confused? Or is it a typo... If yes I'll elaborate it thoroughly. :)
please elaborate it or please answer all the number questions PLEASE
how about the others?? please answer it to me
The Brainliest Answer!
The standard form of quadratic equation is ax^2 + bx + c = 0
where a, b and c are constant values. 
In this one a=2b=5 and c=3

so in no. 1. 3x-2 x^{2} =7
1.2 x^{2} -3x+7=0

so your answer should be in this form:
a x^{2} +bx+c=0
1 5 1
how about the others??
Ohh that's quite a lot it is easy to solve but hard to type it.
answer it and leave those you find hard to solve and I can solve it for you..
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