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Find the equation of the parabola whose vertex is at (0,0) and satisfying the given conditions.

With axis on x-axis and passing through (-4,-6).

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by djdelacruz19

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With axis on x-axis and passing through (-4,-6).

by djdelacruz19

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Since it passes though (-4,-6), then it opens either left or downward, but since it is parallel to the x-axis, then it opens to the left. The equation of the parabola that opens to the left with vertex at the origin is:

y²=4ax

You are given the coordinates, use the coordinates to find a by substituting.

(-6)²=-4a(-4)

36=16a

a=9/2

Substitute the value of a in the equation.

y²=4(9/2)x

y²=18x

The equation of the parabola is y²=18x. Hope this helps =)

y²=4ax

You are given the coordinates, use the coordinates to find a by substituting.

(-6)²=-4a(-4)

36=16a

a=9/2

Substitute the value of a in the equation.

y²=4(9/2)x

y²=18x

The equation of the parabola is y²=18x. Hope this helps =)