Answers

2014-06-08T08:47:32+08:00
Let x be the cost of Blouse

let x+600 be the cost of pants

Given:
 C_{tolal}

Formula:
 C_{Total} =  C_{Pants} +  C_{Blouse}

Solution:

Cost of Blouse

 C_{T} = (x+600)+(x)

 1200 = (x+600)+(x)

1200=2x+600

1200-600=2x

600=2x

 \frac{600}{2} =x

x=Php300.00

solve for cost of pants

 C_{Pants} =300+600

 C_{pants} = Php900.00

Cheking:

 C_{Total} = C_{Pants} + C_{Blouse}

 1200 = 900 + 300

 1200 = 1200
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2014-06-09T20:29:08+08:00
1200=(600+x)+x
1200=600+2x
1200-600=2x
600=2x
600/2=x
300=x
         

checking:x=300
1200=900=300
1200=1200

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