Answers

2015-02-21T14:09:59+08:00
Tan α =  \frac{6.67}{25}
      α = 14 degree 56' (sorry, there's no degree symbol here)

Let x be the distance of the basketball player from the light
tan 14 degree 56' =  \frac{15}{25 + x}
               25 + x =  \frac{15}{tan 14 degree 56'}
               25 + x = 56.22
                      x = 56.22 - 25
                      x = 31.22 ft --> answer
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