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2015-02-21T09:38:03+08:00

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The first diagonal-x
The second diagonal-y

y=2x
because it says one diagonal is twice the other
x+y=24
The sum of the length of the diagonals is 24. Therefore substitute the value of y.
x+2x=24
Add like terms
3x=24
Divide both sides by 3
x=8

Therefore the first diagonal is 8 and the second is 16. Now the formula for the area of the rhombus given its diagonals is:
A=\frac{pq}{2}
Substitute the diagonals
A=\frac{(8)(16)}{2}
A=\frac{128}{2}
A=64 sqr. units

The area is 64 sqr. units. Hope this helps =)
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