Answers

2015-02-23T20:10:22+08:00

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Perpendicular to line y=7x+1 (rearranging it) -> 7x-y=1

for a line to be perpendicular just interchange the constant of the 2 variables and change the sign of y

x+7y+P=0

now we have to solve for P using the formula of distance from a line to a point

d=| (Ax_{1} + By_{1} + P)/(sqrt(A^2 + B^2)) | (absolute value)

where:
d=sqrt2
x_{1}=4
y_{1}=-2
A=1
B=7

sqrt2=| { (1*4) + (7*-2) + P }/(sqrt50) |

solving for P gives you P=20 so the line is x+7y+20=0
0