Answers

2014-06-08T11:47:33+08:00
Let:
 P_{1}=(12,-3)
 P_{2}=(2,3)
 P_{3}=(-3,6)

Solution:

distance from  P_{1} to  P_{2} to  P_{3}

d= \sqrt{(2-12)^2 + (3-(-3))^2} + \sqrt{(-3+2)^2+(6-3)^2}

d=14.824
1 1 1
I'll continue later.. im hungry..
Okey . hope u will do it