ONE AND TWO. A company is going to make frames as part of a new product they are launching.The frame will be cut out of a piece of steel, and to keep the weight down, the final area should be 28 cm^2.The inside of the frame has to be 11 cm by 6 cm.
Area of steel before cutting:
= (11 + 2x) × (6 + 2x) cm^2
= 66 + 22x + 12x + 4x^2
Quadratic Equation = 4x^2 + 34x + 66
Area of steel after cutting out the 11 × 6 middle:
= 4x^2 + 34x + 66 - 66
Quadratic Equation = 4x^2 + 34x
THREE. A ball is thrown straight up, from 3 m above the ground, with a velocity of 14 m/s.
Add them up and the height h at any time t is:
h = 3 + 14t - 5t^2
Quadratic Equation : -5t^2 + 14t + 3 = 0