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First solve for the distance between the 2 ends of the line segment which are (3,2) and (-6,-7). 
In short the distance between 
(3,2) to (-6,-7).

d= \sqrt{( x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }



D= \sqrt{( -6-3)^2+(-7-2)^2 }

D=9 \sqrt{2} or 12.728 units

then solve the distance from (3,2) to (-3,-4)

using the same formula:

d= \sqrt{( x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }


d_{1}= \sqrt{( -3-3)^2+(-4-2)^2 }

d_{1}=6 \sqrt{2} or 8.485 units

solve for d_{2} = D-d_{1}

d_{2} =9 \sqrt{2}-6 \sqrt{2}

 d_{2} =3 \sqrt{2} or 4.423 units


3 \sqrt{2}:6 \sqrt{2}

2 4 2
Ahhh , so thats all ?? thnks u verry much . U help a lot. Im gonna review it and understand . Thnk you .
A cricle has its center of (-1,7) and one of its diamter is at (1,2). Find the other end of this Diameter. How about this ? ur genuis .
what is this your home work? wait my back is aching chair isn't comfortable,.. hehe
and need to take a bath..
please . Last question .
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