Answers

2015-03-24T21:23:13+08:00
The question stated that the lot figure is a rectangle because of the given of length and width.

P=2(l+w)--- where
                P= perimeter --l= length -- w= width
58m= 2(17.5+w)
58= 35+2w
w= 11.5 meters
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2015-03-31T16:13:38+08:00

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What is the width of a lot with a perimeter of 58 meters and a length of 17.5 meters?

Perimeter = 2(length)+2(width)

Given: 
Length = 17.5 meters
           Perimeter = 58 meters

Required: Width

Equation: Perimeter = 2(length)+2(width)

Solution: 58 meters = 2(17.5 meters) + 2n
               58 meters = 35 meters + 2n
               -2n = 35 meters - 58 meters
               -2n = -23
                \frac{-2n}{-2} =  \frac{-23}{-2}
              n = 11.5

Answer:
The width of the lot with a perimeter of 58 meters and a length of 17.5 meters is 11.5 meters.

Check: 
Perimeter = 2(length)+2(width)
            58 meters = 2(17.5 meters) + 2(11.5 meters)
            58 meters = 35 + 23 meters
            58 meters = 58 meters
   

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