# What is the width of a lot with a perimeter of 58 meters and a length of 17.5 meters?

2
by Ramonedusty297

2015-03-24T21:23:13+08:00
The question stated that the lot figure is a rectangle because of the given of length and width.

P=2(l+w)--- where
P= perimeter --l= length -- w= width
58m= 2(17.5+w)
58= 35+2w
w= 11.5 meters
2015-03-31T16:13:38+08:00

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What is the width of a lot with a perimeter of 58 meters and a length of 17.5 meters?

Perimeter = 2(length)+2(width)

Given:
Length = 17.5 meters
Perimeter = 58 meters

Required: Width

Equation: Perimeter = 2(length)+2(width)

Solution: 58 meters = 2(17.5 meters) + 2n
58 meters = 35 meters + 2n
-2n = 35 meters - 58 meters
-2n = -23

n = 11.5