Solve the following problems


1.Separate 60 into two parts such that one number is one-third of the other.
2. Eight less than three times a number is 36 more than one-fourth of the number.
3.The sum of twonumber is 32.The larger is 1 more than twice the smaller number,find the number.
4.The sum of three numbers is 100.The second number is 2 more than three times the first number, and the third number is the sum of the first two number. what are the number?
5.Find the two consecutive integers whose sum is 223.
6.Find the 3 consecutive even integers whose sum is -78.
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. help me pls.. of my assignment

1

Answers

  • Yhi
  • Ambitious
2015-03-07T14:27:52+08:00

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1. 45 & 15 (I solved it through mental math)
2. 1/4x+36=3x-8
36+8=3x-1/4x
(4)(44) = (11/4x)(4)
176/11=11x/11
x=16
3.Sorry I don't have an answer for this problem since there is no number that will be twice and the other number is more than 1 and if you add them it will result to 32
4. let a = 1st num;
let b = 2nd num
       = 3a+2
let c = 3rd num
       = a+b
a+3a+2+a+3a+2 = 100
8a + 4 = 100
8a = 100 - 4
8a/8 = 96/8
a=12
b= 3(12)+2=38
c=12+3(12)+2=50

12+38+50 = 100
5. let x = y+1
let y = 2nd num

x+y=223
y+1+y = 223
2y = 223 - 1
2y/2 = 222/2
y=111
x= 111 + 1 = 112
x+y=223
112+111=223

6. a+b+c=-78
let a - first num
let b - a+2
let c - a+4

a+a+2+a+4 = -78
3a+6=-78
3a=-78-6
3a/3=-84/3
a=-28
b=-28+2=-26
c=-28+4=-24

-28-26-24=-78
0
I was wrong there is an answer for the problem number 3
x+y = 32
let x = 2y+1
y = smaller number

2y+1+y = 32
3y=32-1
3y=31
y=31/3
x=2y+1=65/3

31/3+65/3 = 32
:-)