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2015-03-31T09:41:27+08:00

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Given:

               Price of the electricity = P1.5 per kilowatt-hour

               Electric Bulb = device used

               Wattage of the Electric Bulb = 25 watts

               Range of time used = 8: 00 pm - 5: 00 am in 1 month

Find:

          Payment out from the variables.


Solution:

  Step 1:  We get the wattage of the device used.

  Step 2 : We get the number of hours the device was used.

  Step 3: We multiply the wattage with the number of hours used.

  Step 4: We change the unit to kilo-watt hours.

  Step 5: We multiply the result by the price.


Wattage = 25 watts

Number of hours used = 8:00 pm - 5:00 am = 9 hours

( I assumed that 1 month = 30 days)

30 x 9 hours = 270 hours


25 watts x 270 hours = 6, 750 watt-hours

  6, 750 watt-hours x  \frac{1 kW}{1000 watts} =  \frac{6, 750 watt-hours (kW)}{1,000watt}  = 6. 75 kWh or 6. 75 kilo-watt hours


6. 75 x P1.5 = P10. 125


Final Answer:   P10.125


               

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