Answers

2015-03-30T20:11:25+08:00

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Given:
                Salary for the year = P68, 200

Find:
          Salary for a month

Solution:
               1 year = P68, 200  
               1 year = 12 months
               1 year = 12 months = P68, 200
                12 months = P68, 200
               
                  \frac{12-months = P68, 200}{12}
  
                 1 month = P5, 683. 33 (needs to be rounded up)

Final Answer:
                         P5, 684 (rounded up)


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2015-03-31T20:55:16+08:00

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\bold{Given:} \\ .\ \bold{_{Salary}}\ \ \ \ \ \ \ \ \ \ \ \ \bold{_{Time}} \\ .\ \ \downarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow \\ ^{\bold{Php}\ 68,200}\ \ \ \ \ \ \ \ \ \ \bold{^{year}} \\ .\ \ \ \ \ \ \ \ \ \ _{\bold{(Problem)}} \\ \bold{_{What\ is\ the\ monthly\ salary?}}
^{------------------------------------------------}

\bold{Solution:} 
^{------------------------------------------------}
\\ \\ _{\bold{Equation:}} \\ \\ \bold{Php}\ 68,200}={1\ \bold{year}

1\ \bold{year}=12\ \bold{months} \\ \\ 1\ \bold{year}=12\ \bold{months}=\bold{Php}\ 60,200 
^{------------------------------------------------}
\bold{Final\ Solution:} \\ \\  \frac{\bold{Php}\ 60,200}{12\ \bold{months}}=\bold{Php}\ 5,683.33 \\ \\ \bold{Php}\ 5,683.33\ _{\bold{(round\ up)}}=\ \boxed{\boxed{\bold{Php}\ 5,684}} \\ \\ \bold{Conclusion}:\\ \\ Therefore,\ Teamin's\ father\ earns\ \underline{\bold{Php}\ 5,684}}\ a\ month.

^{------------------------------------------------}

Hope\ it\ Helps:) \\ Domini
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