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2015-04-28T20:52:08+08:00

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Formula for the distance formula
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
d=\sqrt{10}

\sqrt{10} = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
Since the abscissa and ordinate are equal we can either say x_2=y_2
Substitute the (-1,-3)
\sqrt{10} = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
\sqrt{10} = \sqrt{(x_2+1)^2+(y_2+3)^2}
square both sides
10=(x_2+1)^2+(y_2+3)^2
Distribute
10=(x_2)^2+2x_2+1+(y_2)^2+6y_2+9
Substitute
10=(x_2)^2+2x_2+1+(x_2)^2+6x_2+9
Add like terms
10=2(x_2)^2+8x_2+10
Subtract both sides by 10, then divide both sides by 2
0=(x_2)^2+4x_2
Add 4 to both sides (completing the square)
4=(x_2)^2+4x_2+4
4=(x_2+2)^2
Square root both sides
posineg2=x_2+2
Subtract both sides by 2
posineg2-2=x_2
x_2=0 or x_2=-4
(0,0) or (-4,-4)

Hope this helps ^-^
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