Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions



This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Please check the picture attached to understand it more:

The Pythagorean Theorem states that for a right triangle 

In terms of points in the Cartesian plane a is equal to x_a-x_b=a
And b=y_a-y_b

(x_a-x_b)^{2} + (y_a-y_b)^{2} =c^2

Here since 3\ \textgreater \ -3,  (3,y)=(x_a,y_a) \\ (-3,-1)=(x_b, y_b)

We already know the value of c
(3-(-3))^{2} +(y-(-1))^{2} = \sqrt{45} ^2 \\ 6^2+(y+1)^2=45 \\ 36+(y+1)^2=45 \\ (y+1)^2=9

There are 2 cases 

1st Case :
y+1 is equal to the positive squareroot of 9
(y+1)^2=9 \\ y+1= \sqrt{9}  \\ y+1=3 \\ y=2

2nd case:
y+1 is equal to the negative squareroot of 9
(y+1)^2=- \sqrt{9}  \\ y+1=-3 \\ y=-4

Therefore y={-4, 2}
Either of the two are possible

0 0 0
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts