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2015-05-05T18:08:14+08:00

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Okay, gagawin ko siyang simple lang

So ang quadratic equation is in the form:
a x^{2} +bx+c=0
where a \neq 0

x^2+7=3x^2
subtract  x^{2} from both sides
7=2x^2
Subtract 7 from both sides 
0=2x^2-7

The quadratic formula is:
 \frac{-b+ \sqrt{b^2-4ac} }{2a} and  \frac{-b- \sqrt{b^2-4ac} }{2a}
Since x has two roots

So we plug in the values:
 \frac{-(0)+ \sqrt{0-(4)(2)(-7)} }{2(2)}  \\  \frac{ \sqrt{56} }{4}  \\  \frac{2 \sqrt{14} }{4}  \\  \frac{ \sqrt{14} }{2}

The other root is the negative value of this which is - \frac{ \sqrt{14} }{2}

The values of x are  \frac{  \sqrt{14}}{2} and - \frac{ \sqrt{14} }{2}

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