# Mr. Agpalo paid Php 260 for 4 adult’s tickets and 6 children’s tickets. Suppose the total cost of an adult's ticket and a children’s ticket is Php 55. How much does an adult's ticket cost?

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by moorechien19

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by moorechien19

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We let the price of an adult's ticket be A and C for children.

We have two equations:

4A + 6C = 260...[1]

A + C =55 ... [2]

We need to remove C in order to know the value of A so:

6[2] - [1]

6A + 6C = 330

__-4A - 6C = -260__

2A = 70

A = 35

Therefore the cost of an adult's ticket is P35

We have two equations:

4A + 6C = 260...[1]

A + C =55 ... [2]

We need to remove C in order to know the value of A so:

6[2] - [1]

6A + 6C = 330

A = 35

Therefore the cost of an adult's ticket is P35

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Lets represent:

x=cost of adult ticket

y=cost of children ticket

The equation are

4x+6y=260

x+y=55

For the second equation, find the value of x

x+y=55

x=55-y

After finding it, substitute it to the first equation

4(55-y)+6y=260

220-4y+6y=260

Add like terms

220+2y=260

Subtract both sides by 220

2y=40

y=20

Substitute the value of y to any equation

x+y=55

x+20=55

Subtract both sides by 20

x=35

Hope this helps =)

x=cost of adult ticket

y=cost of children ticket

The equation are

4x+6y=260

x+y=55

For the second equation, find the value of x

x+y=55

x=55-y

After finding it, substitute it to the first equation

4(55-y)+6y=260

220-4y+6y=260

Add like terms

220+2y=260

Subtract both sides by 220

2y=40

y=20

Substitute the value of y to any equation

x+y=55

x+20=55

Subtract both sides by 20

x=35

Hope this helps =)