Answers

2015-05-14T20:53:55+08:00

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We let the price of an adult's ticket be A and C for children.

We have two equations:
4A + 6C = 260...[1]
A + C =55 ... [2]

We need to remove C in order to know the value of A so:
6[2] - [1]
 6A + 6C = 330
-4A - 6C = -260
     2A   = 70
       A   = 35

Therefore the cost of an adult's ticket is P35


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2015-05-15T19:05:10+08:00

This Is a Certified Answer

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Lets represent:
x=cost of adult ticket
y=cost of children ticket

The equation are
4x+6y=260
x+y=55

For the second equation, find the value of x
x+y=55
x=55-y
After finding it, substitute it to the first equation
4(55-y)+6y=260
220-4y+6y=260
Add like terms
220+2y=260
Subtract both sides by 220
2y=40
y=20

Substitute the value of y to any equation
x+y=55
x+20=55
Subtract both sides by 20
x=35

Hope this helps =)
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