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2015-05-22T19:59:20+08:00

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Note that:
x^2 \geq 0
This is for any real number x.

Also a number is always less than its square unless it is equal to 0 (because this would make the square 0 as well) so for the number to exceed its square by the maximum amount that number needs to be 0, because this will make their difference be 0.
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