# Eric is twice as old as his brother Lucas. If 4 is subtracted from Eric's age and 4 is added to Lucas' age, their ages will be equal. What are the boys' ages now?

2
by Allanmiraflor160

2015-05-22T18:07:27+08:00

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Lets represent:
x=Eric's age
y=Lucas's Age

The first equation:
x=2y

The second equation:
x-4=y+4
Substitute
2y-4=y+4
Subtract y to both sides
y-4=4
y=8

Therefore: Lucas's age is 8 while Eric's age is 16.

Hope this helps =)

2015-05-22T21:00:45+08:00

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
We let Lucas' age be x, this would make Eric's age 2x.
From the second sentence we would have;

Therefore Lucas' age is 8 and Eric's is 2*8 or 16.