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The lenght of the swimming pool is 8m longer than its width and the area is 105m² ???

plss answer this problem i dont know this....plsss

1
by bjginggoy

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plss answer this problem i dont know this....plsss

by bjginggoy

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Hi so this is how you solve it:

We let the width of the swimming pool be x, this would make the length be x + 8 since it is 8m longer than the width.

So:

Area = length * width

105m² = (x+8)m*(x)m

105= (x+8)(x)

105= x² +8x

0 = x² + 8x - 105

Method 1: Guess and Check

We look for two numbers with a product of 105 and a difference of 8 so:

105 - 1 = 104 X

35 - 3 = 32 X

21 - 5 = 16 X

15 - 7 = 8 √

So,

0 = x² + 8x - 105

0 = (x-7)(x+15)

We equate each to zero (since one factor needs to be zero in order for the product to be zero)

If (x-7) = 0 If (x+15) = 0

x = 7 x = -15

We cannot have a negative length so the width is equal to 7m and the length is equal to 15m.

Method 2: Quadratic Formula

x² + 8x - 105.

x=__-8 ____± √(8²+420)__ = __-8 ± √(64+420)__ = __-8 ± √484__ = __-8 ____± 22__ = 7 or -15

2 2 2 2

So then again, a length cannot be negative so the width is equal to 7m and the length is equal to 15m.

We let the width of the swimming pool be x, this would make the length be x + 8 since it is 8m longer than the width.

So:

Area = length * width

105m² = (x+8)m*(x)m

105= (x+8)(x)

105= x² +8x

0 = x² + 8x - 105

Method 1: Guess and Check

We look for two numbers with a product of 105 and a difference of 8 so:

105 - 1 = 104 X

35 - 3 = 32 X

21 - 5 = 16 X

15 - 7 = 8 √

So,

0 = x² + 8x - 105

0 = (x-7)(x+15)

We equate each to zero (since one factor needs to be zero in order for the product to be zero)

If (x-7) = 0 If (x+15) = 0

x = 7 x = -15

We cannot have a negative length so the width is equal to 7m and the length is equal to 15m.

Method 2: Quadratic Formula

x² + 8x - 105.

x=

2 2 2 2

So then again, a length cannot be negative so the width is equal to 7m and the length is equal to 15m.