# plz. Answer thisThe perimeter of the rectangle is 32m and its area is 48m². Find the length and width of the rectangle

2
by miagi

2014-06-10T09:32:07+08:00

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Let x be the length
y be the width

2x + 2y = 32  (perimeter). If we simplify we have
x + y = 16    ––> Eq1
xy = 48             ––> Eq2 (area)

y = 16-x    ––> from Eq1.  Substitute this to Eq2

x(16-x) = 48
16x -x² = 48
0 = x² -16x +48
0 = (x-4)(x-12)
(x-4)=0 or (x-12)=0
x=4 or x=12

The length and width are 4m and 12m. These may be interchanged since we do not know which is longer.

tnx po
you're welcome :)
2014-06-10T16:32:23+08:00

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86 cm hope i answer correctly