# How many terms are there in arithmetic sequence with a common difference of 4 and with first and last terms 3 and 59, respectively?

2
by Popmars

2015-06-05T22:06:57+08:00

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The formula is:

So there are 15 terms.
2015-06-06T09:31:53+08:00

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Formula:

59 =  - the nth term or could be the last term
3 =  - the first term
4 = d - the common difference
? = n - the number of terms, the one we are solving for
(Substitute)

59 = 3 + (n -1) 4
59 = 3 + 4n - 4
59 = 4n -1
59 + 1 = 4n
60 = 4n
60 / 4 = 4n /4
15 = n

So, n = 15.

There are 15 terms in the sequence.