Answers

2015-06-05T22:06:57+08:00

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The formula is:
n= \frac{a_n-a_1}{d} +1= \frac{59-3}{4} +1= \frac{56}{4} +1=14+1=15

So there are 15 terms.
1 5 1
2015-06-06T09:31:53+08:00

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Formula:
                t_{n} =  t_{1} + (n-1)d

59 =  t_{n}  - the nth term or could be the last term 
 3 =  t_{1} - the first term      
 4 = d - the common difference
 ? = n - the number of terms, the one we are solving for
(Substitute)

  t_{n} = t_{1} + (n-1)d

59 = 3 + (n -1) 4
59 = 3 + 4n - 4
59 = 4n -1
59 + 1 = 4n
60 = 4n
60 / 4 = 4n /4
15 = n

So, n = 15.

There are 15 terms in the sequence.
3 4 3