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2015-06-06T11:19:42+08:00

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Okay, I am assuming that  a_{1} is equal to  t_{1}

Formula:
                a_{n} =  a_{1} + (n -1) d
Substitute:
                n for 9
                a_{1} for 10
                d for  -\frac{1}{2}
Solution:
                a_{9} = 10 + ( 9 -1)- \frac{1}{2}
                  a_{9} = 10 + 8 (- \frac{1}{2} )
                  a_{9} = 10 + -4
                   a_{9} = 10 - 4
                    a_{9} = 6
Check:
  First 9 terms:           10, 9.5, 9, 8.5, 8, 7.5, 7, 6.5, 6

Answer:
               The 9th term is 6.

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2015-06-06T22:24:21+08:00

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a_n=a_1+(n-1)d \\ a_9=10+(8)(-1/2)=10-4=6
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