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Please note the following: 1st term=30, nth term=101834, d=2

S_n=a_1+(a_1+d)+(a_1+2d)+...+[a_1+(n-1)d] \\ =a_1n+ \frac{n(n-1)d}{2}  \\ = \frac{2a_1+n(n-1)d}{2}  \\  =\frac{n(2a_1+(n-1)d)}{2}  \\ = \frac{n(a_1+a_n)}{2}

n= \frac{a_n-a_1}{d} +1= \frac{101834-30}{2} +1=50903

S_n= \frac{50,903(30+101,834)}{2} = \frac{50,903(10,1864)}{2} =2,592,591,596