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Mr.s Jacinto asked a carpenter to construct a rectangular bulletin board for her classroom. She told the carpenter that the boards area must be 18 square

1. what are the possible dimension of the bulletin board?
2. how did you determine the possible dimensions of the bulletin board?
3. suppose the length of the board is 7 ft. longer than its width. what equation would represent the given situation
4.how would you describe the equation formulated
5: do you think you can use the equation formulated to find the length and the width of the bulletin board? justify ur answer.
i neeed itt!!!! huhuhubels.


2. Possible dimensions of the bulletin board: 2 ft. by 9 ft. and 3 ft. by 6 ft. 
3. Find two positive numbers whose product equals 18. (Note: Area = length x width) 
4. Let w be the width (in ft.). Then the length is w + 7. Since the area is 18, then w(w+7)=18. (Other variables can be used to represent the length or width of the bulletin board) 
5. Taking the product on the left side of the equation formulated in item 4 yields w2+7w=18 . The highest exponent of the variable involved is 2. 
6. Yes 

Hope it's correct :)))
4 5 4
LOL agad agad? hahaha
hahaha, i hate math
nag dudugo yung ilong ko
Opposite tayo :3 Pinakagusto ko talga yung Math
haha xD science and english lang ang kaya ko.
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