# Example of a Quadratic Equation with Two Real Solutions, One Real Solutions and No Real Solutions

1
by natzhoran

2015-06-10T13:12:15+08:00

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Δ refers to the discriminant which is under the squareroot sign in the quadratic equation which is b²-4ac

Case 1. Δ≥0, the roots are real

1.1 Δ>0, there are 2 real solutions
This means b²>4ac. We can simply give x²+3x+2. That is  (x+1)(x+2)

1.2 Δ=0, there is only one root
This would mean b²=4ac. We can simply give (x+1)² or x²+2x+1

For Case 1.2, it is like this since if we check the quadratic formula:
-b ± √0 = -b
2a       2a

Case 2. Δ<0, there are no real solutions.
Since we would need to get the squareroot of a negative value, which is imaginary.

This would mean b²<4ac. To give an easy example we let a=b=c=1 so x²+x+1.