Answers

2015-06-13T18:03:44+08:00

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
The number would be abcd, then the reverse is dcba. 
The number is equal to 1000a+100b+10c+d
The reverse is equal to 1000d+100c+10b+a

(1000a+100b+10c+d) + (1000d+100c+10b+a)=5555
1001(a+d) + 110(b+c) = 5555
11[91(a+d)+10(b+c)] = 5555
91(a+d) + 10(b+c) = 505
10(b+c) = 505-91(a+d)

This is a diophantine equation... Take note that the ones digit 5, will come from 91.

We can only have : a + d = 5
10(b+c) = 505 - 91(5)
10(b+c) = 505 - 455 = 50
Therefore b+c = 5

5 = 1+4 , 2+3 or 0+5
This would mean a is equal to 1 since we want the least number, and we cannot have 0 as a. This would then make d=4. We also have b=2,c=3

The number then is 1234.


0