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2015-06-14T13:18:59+08:00

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We are looking for √7084. We should first factor out 7084 by continuous division:
4  | 7084    It is divisible by 4 since the last two digits are divisible by 4
11 | 1771  It is divisible by 11 since the alternating sum is 0   
 7  | 161          
       23                 
So we know √7084 = √(2² x 7 x 11 x 23) = 2√(7 x 11 x 23) = 2√1771
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