# The following are the values of a,b and c that edna and luis got when they expressed5-3x=2x² in standard form what do you think got the correct values of a,b and c justify your answer.

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by joshly

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by joshly

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Lets remember the standard form of quadratic equations, that is Ax^2 + Bx + C = 0.

The given equation is:

5 - 3x = 2x^2

Transforming it to standard form by transposing all terms in the LEFT SIDE of the equation,we will have:

-2x^2 - 3x + 5 = 0

where a = -2 , b = -3 , c = 5

Transforming it to standard form by transposing all terms in the RIGHT SIDE of the equation,we will have:

0 = 2x^2 + 3x - 5

where a = 2, b = 3, c = -5

Conclusion both Edna and loisa are correct actually.