In the figure, circle O is inscribed in equilateral triangle ABC and X , Y and Z are the points of tangency. If the side of triangle ABC is 12, how long is the radius of circle O.

full solutions please and thank you :)

2
The length of one side :)
are you a college student?
done
no haha :))
di mo na gets?

Answers

2014-06-13T17:38:31+08:00

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Given:
side = 12

see figure:

a right triangle is formed.

where the hypotenuse is. h - r
and the other sides are r and 12/2

h= \sqrt{6^2+12^2}

h=10.39

to get the radius we use the Pythagorean theorem.

10.39-r= \sqrt{(r)^2+(6)^2}

r=3.46
1 5 1
did you get it ask if there anything you didn't get.
how did the hypotenuse become 12 - r *question mark* haha sorry
oh thats right my mistake
i will edit again
haha thank you so so much! :D
2014-06-13T17:50:27+08:00

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
r = 2 √3

See attached for solution. :)
Btw, I used trig functions, because it is the easiest way to solve it. Haha. I hope you're familiar with that.


<XBO is 1/2 of <XBA. That is why it's 30º
1 5 1
ooooh. thank youu! I am familiar with it :) Thank you! :)
well taking picture seems to be a lot easier. hehehe
Yup :)