# How many terms are there in an arithmetic sequence with a common difference of 4 and with first and last terms 3 and 59,respectively?

1
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answer:

59=3+(n-1)4

59=3+4n-4 (transpose +3 and -4)

59-3+4=4n

60=4n

(to eliminate 4 in 4n, divide both 60 and 4n by 4)

so...

60/4=4n/4

15=n

n=15

there are 15 terms...