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## Answers

(2x+y+3z) times (2x+y+3z)

2x is the first term

y is the second term

3z is the third term

You need to multiply the first term to first term

next first to second

first to third

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2x times 2x = 4x^2

2x times y= 2xy

2x times 3z= 6xz

this is the first batch 4x^2+ 2xy+6xz

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next is Second term to first term

second to second

second to third.

--

y times 2x = 2xy

y times y= y^2

y times 3z= 3yz

the seond batch of equation is 2xy+y^2+3yz

--

Then, the third term to first

third to second

third to third.

--

3z times 2x =6xz

3z times y= 3yz

3z times 3z= 9z^2

--

thas is the last batch 6xz +3yz+9z^2

--

Thats like destributive property :)

Now combine like terns,

--

4x^2+ 2xy+6xz

2xy+y^2+3yz

6xz +3yz+9z^2

the answer is

--

4x^2+4xy+12xz+y^2+6yz+9z^2

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The same process with the next one. Hope it helps