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In squaring, if it is at least two digits, then the ones or the digit in the right side, multiply it by itself. then that's your ones in your answer or your first digit. if the answer is two digit or more, then you must carry them like you do in multiplying vertically in the tens. then , for finding the tens or the second digit, multiply the first and second digit then twice it's product. then for the hundreds or thousands, the tens of the original form will be multiply by itself.

          25^2 =  (5)^2 - ones
                    = [(5)(2)]^2 -tens
                    = (2)^2 - hundreds
hence, it is equal to
0 0 0
Use calculator. Do this! for example cube root of 8? √8^1÷3
0 0 0
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