# CALCULUS :Direction: Find the derivatives of the following functions using any of the two methods1. f (x) = x²-4x ---------- = x+1 2. f (x) = 3x -------- = x +4 3. f(x)= x+1 ---------- = x³ 4. y = x² --------- = x+2x 5 . f(x) = x-2 ---------- = x³Please answer :)i need Solution & perfectly answer tnx god bless mwaaahh... :*

1
by pilyangmojacko

2014-01-21T17:13:03+08:00
1. f (x) = x²-4x
---------- =
x+1

= (x²-4x)
remember that (f)(g) = f'g+g'f
=
=

2. f (x) =  3x
-------- =
x +4
= 3x
=
=12/

3. f(x)= x+1
---------- =
x³
=
=
=

4. y = x²
--------- =
x+2x
multiply 1/x to the numerator and denominator
you get:
=
=
=1/3
5 . f(x) = x-2
---------- =
x³
sorry in number 4, there might've been a problem with how i wrote the equation....anyway it's supposed to be x/(2+1). Since you can remove the constant (1/3), you just need to get the derivative of x which is 1. So (1/3)(1) = 1/3