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(b+5c)cube may 3 sa taas
0 0 0
ay mali
ganito po yung gagawin ex. r3t3-64 =(rt-4)(rt)²+(rt)(4)+(4²) = (rt-4)(r²t²+4rt+16) ganyan po pero difference po yan di lang po ako sure sa answer ko dun sa b³+125^6
Pag itsura:
pag factor
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factoring of sum or difference of two cubes po ang gagawin dapat po may solution pls po paki sagot
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