Answers

2015-07-07T18:05:16+08:00
(b+5c)cube may 3 sa taas
0
(b+125c^6)
ay mali
(b^3+125^6)
(b+5c^2)
ganito po yung gagawin ex. r3t3-64 =(rt-4)(rt)²+(rt)(4)+(4²) = (rt-4)(r²t²+4rt+16) ganyan po pero difference po yan di lang po ako sure sa answer ko dun sa b³+125^6
2015-07-07T18:11:47+08:00
Pag itsura:
(b+125^3)^3
pag factor
Use Special products to answer that

0
factoring of sum or difference of two cubes po ang gagawin dapat po may solution pls po paki sagot