# NCAE Chemistry: An aqueous solution contains 64.0 g of ethanol (C2H5OH) in 122.0 g solution. What is the mole fraction of ethanol in the solution? a. 0.205 c. 0.302 b. 0.432 d. 0.70

1
by gaeamiraflor212

2015-07-09T19:19:12+08:00

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GIVEN:
Amount of ethanol = 64 grams
Total amount of solution = 122 grams
Amount of water = 122 grams - 64 grams = 58 grams

Molecular weight of C2H50H:
C2 = 12 (2) = 24
H5 = 1 (5) = 5
O = 16
H = 1
TOTAL= 46 grams

Molecular weight of H2O:
H2 = 1(2) = 2
O = 16
TOTAL = 18 grams

STEP 1: Convert grams to moles.

C2H50H
64 g. C2H50H x 1 mole  = 1.39 moles
46 g.

H20
58 g. H20 x 1 mole  = 3.22 moles
18 g.

TOTAL MOLES OF THE AQUEOUS SOLUTION:

mol C2H5OH + mol H2O = 1.39 + 3.22 = 4.61 moles

STEP 2: Substitute the given to the formula and solve.

mole fraction = mole of component
total mole of solution
= mole of C2H5OH (because it's the one being asked)
total mole of solution
= 1.39 moles
4.61 moles
= 0.302 moles
OMG nakakapagod magtype nun at mag align. Sana naman po pag-aralan niyo ang solution at hindi lang kunin ang sagot. Sayang po effort ko magshare ng solution kung hindi niyo naman pag-aaralan.