Answers

2015-07-11T15:33:33+08:00

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
We let the time taken when ....
the larger hose alone is used be x - 6
and the smaller hose as x.

This would make their rates  \frac{1}{x-6} and  \frac{1}{x}  respectively.

Take note that:
1 / rate = time 
so,
1 / rate of both hoses = 4
rate of both hoses = 1/4

 \frac{1}{x-6} + \frac{1}{x} = \frac{1}{4}\\ \frac{2x-6}{x^2-6x}  = \frac{1}{4}  \\ 8x-24=x^2-6x \\ 0=x^2-14x+24 \\ 0=(x-12)(x-2)

This would mean that x = 12 or 2 but x cannot be 2 since that would make the time taken for the larger hose negative.

Therefore it will take the smaller hose 12 hours to fill the swimming pool alone.
1 4 1