Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

A computer manufacturing company would like to come up with a new laptop computer such that its monitor is 80 square inches smaller than the present

ones.suppose the length of the monitor of the larger computer is 5 inches longer than its width and the area of the smaller computer is 70 square inches.what are the dimensions of the monitor of the larger computer?

Since area of smaller monitor is 70 sq”, and since this area is 80 sq” smaller

than the larger monitor, then area of larger monitor = 150 (70 + 80) sq"

Now, we can say that: W^2+5W=150 ------ W^2+5W-150=0

(W - 10)(W + 15) = 0

Width of larger monitor, or W = 10 inches W = - 15 (ignore)

Length

Let width of larger monitor = W Then length of larger monitor = W + 5 Area of larger monitor = W(W + 5), or W^2+5W Since area of smaller monitor is 70 sq”, and since this area is 80 sq” smaller than the larger monitor, then area of larger monitor = 150 (70 + 80) sq" Now, we can say that: W^2+5W=150 ------ W^2+5W-150=0 (W - 10)(W + 15) = 0 Width of larger monitor, or W = 10 inches W = - 15 (ignore) Length of larger monitor: 10 + 5 = 15 inches

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Asmall = 70

Alarge = Asmall +80 = 70 + 80 = 150 in²

Let x be the width x+5 = length

A = (length)(width) 150 = (x+5)(x) 150 = x² + 5x 0 = x² +5x - 150 0 = (x+15) (x-10) x=-15 ; x=10 [Use x=10 because we can not have a negative dimension]

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

The width of the larger computer is 10 in and the length is 15 in.

Then length of larger monitor = W + 5

Area of larger monitor = W(W + 5), or W^2+5W

Since area of smaller monitor is 70 sq”, and since this area is 80 sq” smaller

than the larger monitor, then area of larger monitor = 150 (70 + 80) sq"

Now, we can say that: W^2+5W=150 ------ W^2+5W-150=0

(W - 10)(W + 15) = 0

Width of larger monitor, or W = 10 inches W = - 15 (ignore)

Length

Then length of larger monitor = W + 5

Area of larger monitor = W(W + 5), or W^2+5W

Since area of smaller monitor is 70 sq”, and since this area is 80 sq” smaller

than the larger monitor, then area of larger monitor = 150 (70 + 80) sq"

Now, we can say that: W^2+5W=150 ------ W^2+5W-150=0

(W - 10)(W + 15) = 0

Width of larger monitor, or W = 10 inches W = - 15 (ignore)

Length of larger monitor: 10 + 5 = 15 inches