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Solving quadratic equation by completing the square. Help me please

1. 5p^2 + 2p -9=0

2. 2y^2 -3y-8=0

1
by arve

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1. 5p^2 + 2p -9=0

2. 2y^2 -3y-8=0

by arve

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ALWAYS REMEMBER the standard form of a Quadratic Equation is

First

So, we can have:

(5p2 + 2p – 9)/5 = 0/5

p2 + 2/5 p – 9/5 = 0

p2 + 2/5 p = 9/5

(B/2)2 = {(2/5)(1/2)}2

= (1/5)2

p2 + 2/5 p + 1/25 = 9/5 + 1/25

This time we have completed the square (the Left side of the equation is a perfect square; it can be factored completely) And we will have:

(p + 1/5)2 = (45+1)/25

(p + 1/5)2 = 46/25

Then take the square root of both sides of the equation for us to get the roots. We have:

p +1/ 5 = √(46/25)

p + 1/5 = (√46)/5

p = +/- (√46)/5 - 1/5

So you now have the roots that will satisfy your equation:

P1 = (√46)/5 - 1/5 p2 = - (√46)/5 - 1/5