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(2a²b³)³ = 8a⁶b⁹

(rs⁵t²)⁻² = 1/(rs⁵t²)² = 1/r²s¹⁰t⁴

(-3x³y)⁰ = 1

(a²b³c)² (abc) = (a⁴b⁶c²) (abc) = a⁵b⁷c²

2m²n²/4n⁻² = m²n⁴/2

4x³y⁻²/x = 4x²/y²

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salamat po
you're welcome :)
I-clarify mo sa teacher mo yung sa #3. Baka nagkamali lang sya ng nasabi.
cge po
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