Answers

2015-07-21T20:32:51+08:00

let 'a' be the length of one side of the larger square

let 'b' be the length of one side of the smaller square

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since we are given that the side length of one lot is 2 meters less than the other then we can have the equation as

b = a - 2    ------equation 1

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Given that the area of the larger square is 44 square meters greater than that of the smaller then we'll have

a² - b² = 44    ----equation 2

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substitute equation 1 to equation 2

a² - (a-2)² = 44

simplify

a² - (a² - 4a + 4) = 44

a² - a² + 4a - 4 = 44

4a = 44 + 4

4a = 48

a = 12 m

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substitute the value of 'a' to equation 1

b = a - 2

b = 12 - 2

b = 10m

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therefore we can say that the smaller square measures 10 x 10 m and the larger square measures 12 x 12 m

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