Answers

2015-07-22T17:22:45+08:00
For special product, use the formula:  (x+y)^{3}  x^{3} + 3 x^{2} y+3x y^{2} + y^{3}

so,  (2x-4y)^{3} =    (2x)^{3} + 3 (2x)^{2} (-4y) +3(2x) (-4y)^{2} + (-4y)^{3}

= 8x^{3} -48x^{2} y+96x y^{2} -64y^{3}
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