Answers

2014-06-25T08:01:16+08:00
Solution:(2/a)squared+(2/b)squared+(2/c)squared+2(2/a)(2/b)+2(2/a)(2/c)+2(2/b)(2/c)=
4a squared + 4b2 +4c2 + 8ab +8ac+8bc

squared=2
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