Answers

2015-08-21T14:35:07+08:00
68 and 56 are the numbers
1 2 1
or you can do trial and error
how did you get th answer can you show me the solution...THE COMPLETE SOLUTION PLEASE!!!!
i actually did trial and error! just be mindful of the numbers that you think are able to satisfy the condition
thank you but can you show me your solution because we will discuss it to our calss
*class
2015-08-21T19:00:56+08:00
Let 'x' be the smaller number
let 'y' be the larger number
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"the sum of the two numbers is 124"
x + y = 124 -equation 1
"three times the smaller number exceeds the larger number by 12"
-equation 2
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from equation 2
3x = y + 12
y = 3x - 12 -equation 3
substitute equation 3 to equation 1
x + y = 124
x + (3x - 12) = 124
x + 3x - 12 = 124
4x = 124 + 12
4x = 136
x = 34
----
substitute x to equation 3
y = 3x - 12
y = 3 (34) - 12
y = 90
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therefore the numbers are 34 & 90

1 1 1
3x = y + 12 -equation 2
thank you!!!!