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2015-08-21T14:39:46+08:00

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It is 54 and 32
54 + 32 = 86
54 - 32 = 22

solution:
a + b = 86
a  - b = 22          add the two numbers
2a     = 108

by multiplication property of equality, divide it to two to cancel out 2a to only a
a = 54

therefore the one digit is 54
54 + b  = 86
86 - 54 = b
86 - 54 = 32

therefore the digits are 54 and 32

1 5 1
the sum of two numbers is 124. three times the smaller number exceeds the larger number by 12. find the numbers.
please
the answer is 90 and 34
sorry it took me longer to solve
thank you
2015-08-21T17:22:31+08:00
54 + 32 = 86
54 - 32 = 22
1 1 1