# The 4 oldest people in golden city live on total of 384 years put together.The difference in age for the youngest and the second oldest is 14 years.The second youngest is 3 years older than the youngest.The oldest is older 20 years than the average of the second oldest and the youngest.What are their ages?.

1
by miana

• Brainly User
2015-09-01T23:38:01+08:00

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Let   youngest = x

2nd youngest =  x + 3

2nd oldest = x + 14

oldest = 20 + (x + x + 14)
2
=  20 + (2x+14)
2
= 20 + x + 7
= x + 27

Total of their ages = 384

Equation:
(x) + (x+3) + (x+14) + (x+27) = 384
4x + 44 = 384
4x = 384 - 44
4x = 340
4       4
x = 85

Their ages if x = 85
Youngest: x     85 yrs. old

2nd youngest : x + 3
85 + 3 = 88 years old

2nd oldest:  x + 14
85 + 14 = 99 years old

Oldest:  x + 27
85 + 27 = 112 years old

To check:
85 + 88 + 99 + 112 = 384
384 = 384

thank you very much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
You're welcome, Miana :-)