# 4 number have a total of 92.The first # is twice the 2nd # and the 3rd # is 4 more than the sum of the first two. The 4th# is 3 less than the difference of the first 2 numbers.What are the numbers?

1
by miana

• Brainly User
2015-09-02T22:45:25+08:00

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Let x be the second number.

Representation:
First number = 2x  (twice the second number)
Second number = x
Third number = (2x+x) + 4 (four more than the sum of the first two numbers)
Fourth number = (2x-x) - 3  (three less than the difference of first two numbers)
Total of the four numbers = 92

Equation:
2x + x + (2x+x+4) + (2x-x-3) = 92
2x + x + 3x + 4 + x-3 = 92

Combine the like terms:
2x + x + 3x + x + 4 - 3 = 92
7x +1 = 92
7x = 92-1
7x = 91
7        7
x = 13

The numbers are:
first number = 2x
= 2(13)
= 26

second number = x
= 13

third number =  2x + x + 4
= 2 (13) + 13 + 4
= 26 + 13 + 4
= 43

fourth number =  2x-x-3
= 2(13) - 13 - 3
= 26 - 13- 3
= 10

To check:
26 + 13 + 43 + 10 = 92
92 = 92