# The product of two consecutive odd integers is 58 less than the square of the next consecutive integer. Find these integer. Show me your soltion please :) BTW OUR TOPIC IS ABOUT QUADRATIC EQUATIONS and solve this using one variable only :)

1
by kisseyofficial
is it "58 less than" or "58 less" ? There's a big difference between the two with regards to the problem given.

• Brainly User
2015-09-04T10:27:35+08:00

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This is linear.

Let the first odd integer = x
second odd integer = X + 2
third odd integer = x+4

(x) (x + 2) = (x + 4)² - 58
x² + 2x = x² + 8x + 16 - 58
x² - x² + 2x - 8x - 16 + 58 = 0

-6x + 42 = 0       (linear equation)

-6x = -42
-6       -6
x = 7

Substitute 7 for x

First odd integer:  x = 7
Second odd integer: x + 2
7 + 2
= 9

third odd integer: x + 4
7 + 4
= 11

The three consecutive odd integers are 7, 9, 11