Solve for the value of the consant of variation k, and then find the missing value.
1.)z varies jointly as the square root of the product of x and y, if z=3 when x=3 and y=12, find x when z=6 and y=64
2.)d varies jointly as h and g. if d=15 when h=14 and g=5, find g when h=21 and h=8.
3) q varies jointly as r and s. if q=2.4, when r=0.6 and s=0.8, find q when r=1.6 and s=.01

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2015-09-04T07:19:51+08:00

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1)  z = k  \sqrt{(x)(y)}
       3 = k  \sqrt{(3)(12)}
       3 = k  \sqrt{36}
        \frac{3}{6}  = k  \frac{6}{6}
       k =   \frac{1}{2}
   
      6 =  \frac{1}{2}  \sqrt{(x)(64)}
      6 =  \frac{1}{2} (8) \sqrt{x}
      \frac{6}{4}  =  \frac{6}{4}   \sqrt{x}
      ( \frac{3}{2}) ^{2} = (   \sqrt{x} )^{2}
     x =  \frac{9}{4}

2.  d = k (h)(g)
     15 = k (14)(5)
     15 = k (70)
       \frac{15}{70}  = k  \frac{70}{70}
       k = \frac{3}{14}
   
     use the equation : 
     
     d = 3/14 (h)(g)   for the next set.  check that your values has no d, but 2 h's

3)  q = krs
      2.4 = k (0.6) (0.8)
      2.4 = k (0.48)
     0.48       0.48
         k = 5
     
      q = krs
      q = 5 (1.6) (0.01)
     q = 0.08




3 5 3
you're welcome. keep practicing :-)
Please note that in number 2, there are two values for h, and none for d. Just follow the equation for set 2
i don't know how o solve number 2. i don't know how. ;(
i don't know how to solve number 2. i don't know how. ;(
Check the values for h and d. Go back to your notes. maybe topographical error. The post the question again. Not in this comment box. Post it in "ask a question"